0=-5t^2+44t

Solution for 0=-5t^2+44t equation:

0=-5t^2+44t

We move all terms to the left:

0-(-5t^2+44t)=0

We add all the numbers together, and all the variables

-(-5t^2+44t)=0

We get rid of parentheses

5t^2-44t=0

a = 5; b = -44; c = 0;
Δ = b2-4ac
Δ = -442-4·5·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-44}{2*5}=\frac{0}{10}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+44}{2*5}=\frac{88}{10}
=8+4/5
$